£9 - 90p = £8.10
2 Pencils = 48p
3 Pens = £1.11
3 Sharpeners = £2.31
All together = £3.90
£8.10 - £3.90 = £4.20
£4.20 / £1.40 = 3
Answer = 3 Notebooks
Answer, step-by-step explanation:
A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:
units sold. relative frequency. Acumulative frequency. interval of random numbers
30. 0.16. 0.16. 0.00 <0.16
40. 0.24. 0.4. 0.16 <0.4
50. 0.3. 0.7. 0.4 <0.7
60. 0.2. 0.9. 0.7<09
70. 0.1. 1. 0.9<1
B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:
random Units
number. sold
0.12. 30
0.96. 70
0.53. 50
0.80. 60
0.95. 70
0.10. 30
0.40. 50
0.45. 50
0.77. 60
0.29. 40
the two lists are compared so that opposite each one is the result of the simulation
Answer:
Choice A
Step-by-step explanation:
(4m^5n^2/m^2n)^3
dividing exponents = subtraction
(4m^3n)^3
4^3 = 64
(m^3 )^3 = m^3x3 = m^9
64m^9n^3
Answer:
ASA
Step-by-step explanation:
in the place that I have put some marks on it, they have the same angle; so then they will also have the same third angle; and for the rest you should use ASA.
Value
Depreciation is defined as the reduction in value of an
asset over time. In this case, value reduction is due to wear and tear of an
equipment (bicycle).
a. The depreciation value would simply be the difference
in initial and salvage value divided by time in years.
Depreciation = (Initial value – Salvage value) / Number
of years
b. Substituting the given values into the equation where:
Initial value = $1200
Salvage value = $940
Number of years = 10 months = 10/12 years
Calculating:
Depreciation = ($1200 - $940) / (10/12 years)
Depreciation = $312 / year
or
<span>Depreciation = $26 / month</span>
