Write an equation in slope-intercept form of the line with slope 4 and a point at (0, -3)*

Whats the awnser x-9.8=24

saveliy_v [14]

The answer is x= 33.8

8 0

3 years ago

Izumi is running on a quarter-mile oval track. After running 110 yards, his coach records his time as 16 seconds.

pickupchik [31]

Answer:

14.04 miles per hour

Step-by-step explanation:

The problem is asking for Izumi's speed. The formula of speed is:

s = $\frac{d}{t}$ , where "s" means speed, "d" means distance and "t" means time.

The problem is also asking for the unit miles per hour ( $\frac{miles}{hour}$ ) so, this means that we have to know how many miles Izumi ran, given that the problem only mentioned yards (110 yards).

Let's convert 110 yards to miles, provided that he Izumi ran 1,760 yards in a mile.

110 yards ÷ 1760 $\frac{yards}{mile}$ = 0.0625 miles (this is the distance covered by Izumi in miles)

Let's go back again to the formula: s = $\frac{d}{t}$

s = $\frac{0.0625 miles}{16 seconds}$ = 0.0039 $\frac{miles}{sec}$

Since, the we arrived at a miles per second unit, we have to convert it to miles per hour.

So, if a minute has 60 seconds, then an hour has 3,600 seconds.

Thus, 0.0039 $\frac{miles}{sec}$ × 3,600 $\frac{seconds}{hour}$ = 14.04 miles per hour (the answer)

3 0

3 years ago

Solve 5x +3>19 what is it

tatyana61 [14]

Answer:

x > 3 1/5

Step-by-step explanation:

5x +3>19

Subtract 3 from each side

5x +3-3>19-3

5x >16

Divide each side by 5

5x/5 > 16/5

x > 16/5

x > 3 1/5

7 0

3 years ago

Emissions of sulfur dioxide by industry sett off chemical changes in the atmosphere that result in "acid rain". The acidity of l

horsena [70]

Answer:

Case n =5

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894$

Case n =15

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549$

Case n = 40

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530$

P value

Case n =5

$p_v =P(z$

Case n =15

$p_v =P(z$

Case n =40

$p_v =P(z$

Step-by-step explanation:

Data given and notation

$\bar X=4.8$ represent the sample mean

$\sigma=0.5$ represent the population standard deviation

$n$ sample size

$\mu_o =5$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 5, the system of hypothesis would be:

Null hypothesis: $\mu \geq 5$

Alternative hypothesis: $\mu < 5$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

Case n =5

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894$

Case n =15

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549$

Case n = 40

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530$

P-value

Since is a left tailed test the p value would be:

Case n =5

$p_v =P(z$