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Zielflug [23.3K]
3 years ago
15

Write an equation in slope-intercept form of the line with slope 4 and a point at (0, -3)*

Mathematics
1 answer:
bogdanovich [222]3 years ago
3 0
Y=4x-3
Follow this equation y=mx+b (m=slope, b= point given)
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2. Henry spends $90.00 on lunch and spends $16.00 on bananas. Hicks
Komok [63]

Answer:

it will cost him $226 and his left over amount will be 24 dollars.

8 0
3 years ago
3. The sum of three consecutive numbers<br> is 42. What are the numbers?
Zanzabum

Answer:

13 + 14 + 15

Step-by-step explanation:

n + (n + 1) + (n +2) =42

n + n + n + 1 + 2 = 42

3n + 3 = 42

(subtract 3 from both sides)

3n = 39

(divide both sides by 3)

n = 13

(solve)

n + (n + 1) + (n +2) =42

13 + (13 + 1) + (13 + 2) = 42

13 + (14) + (15) = 42

13, 14, 15

(Hope this helps, have a nice day!)

3 0
3 years ago
Write or draw to explain a way to find each sum: 6+7, 8+4, 2+9
storchak [24]
Draw six dots then a plus sign then draw seven dots and the count them and put an equal sign and however many dots. Doe the same with the other numbers
6 0
3 years ago
Read 2 more answers
There are currently 18 pit bulls at the pound. Of the 18 pit bulls, four have attacked another dog in the last year. Joe, a memb
laila [671]

Answer: 0.7748

Step-by-step explanation:

Given : Number of bit bulls at the pound = 18

Number of pit bulls have attacked another dog in the last year =4

The proportion of pit bulls have attacked another dog in the last year:p=\dfrac{4}{18}\approx0.22

Number of the pit bulls selected = 6

The probability of that none of the pit bulls in Joe's group attacked another dog last year :  P(0)=(1-0.22)^6=0.225199600704\approx0.2252

By using binomial , the probability that at least one of the pit bulls in Joe's group attacked another dog last year is given by :-

P(x\geq 1)=1-P(x

Hence, the required probability = 0.7748

3 0
3 years ago
A department store has daily mean sales of​ $28,372.72. The standard deviation of sales is​ $2000. On​ Tuesday, the store sold​
DiKsa [7]

Answer:

Tuesday z-score was 3.26.

Tuesday was a significantly good day.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A score is said to be significantly high if it has a z-score higher than 1.64, that is, it is at least in the 95th percentile.

In this problem, we have that:

\mu = 28372.72, \sigma = 2000

On​ Tuesday, the store sold​ $34,885.21 worth of goods. Find​ Tuesday's ​z-score.

This is Z when X = 34885.21

Z = \frac{X - \mu}{\sigma}

Z = \frac{34885.21 - 28372.72}{2000}

Z = 3.26

Tuesday z-score was 3.26.

Was Tuesday a significantly good​ day?

A z-score of 3.26 has a pvalue of 0.9994. So only 1-0.9994 = 0.0006 = 0.06% of the day are better than Tuesday.

So yes, Tuesday was a significantly good day.

8 0
3 years ago
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