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3 years ago

What is the volume of a cylinder with base radius 3 and height 5?

Mathematics

1 answer:

NARA [144]3 years ago

4 0

Answer:

Multiplying by the height h we get

volume = π r 2 h

where:

π is Pi, approximately 3.142

r is the radius of the circular end of the cylinder

h height of the cylinder

Step-by-step explanation:

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Need answer to 4 and 5

algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $g_n = 2 . 3^{n - 1}$

To find the first term, substitute n = 1.

Therefore, $g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1$ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3$ = 6

$g_3 = 2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9$ = 18

$g_4 = 2 . 3^{4 - 1} = 2 . 3^{3} = 2 . 27$ = 54

$g_5 = 2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81$ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $t_n = \frac{2}{3}t_{n - 1}$

$t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1 = \frac{2}{3}6$ = 4

$t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3}$

$t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9}$

$t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27}$

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0

3 years ago

Try it, let's see can u do or not

Firlakuza [10]

Answer:

Step-by-step explanation:

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He solution to the initial value problem x′′+2x′+26x=5cos(4t),x(0)=0,x′(0)=0 x″+2x′+26x=5cos⁡(4t),x(0)=0,x′(0)=0 is the sum of t

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3 years ago

Simplify the expression.<br> 7(6x – 4) + 1

makkiz [27]

Answer:

42x -27

Step-by-step explanation:

we apply distributive property:

7(6x – 4) + 1

7*6x - 7*4 +1

42x - 28 +1

42x -27

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What is the value of y?

AnnyKZ [126]

Answer:y= 47/20

Step-by-step explanation:

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