What is the slope of y=4/5x-5

PLZ HELP...Enter in standard form the equation of the line passing through the given point and having the given slope.

Alenkinab [10]

Standard form for the equation of the line is

$$y=-\frac{2}{3} x-\frac{25}{3}$

Solution:

Given point is (2, –5).

slope of the line m = $-\frac{2}{3}$

Here, $x_1=2, y_1=-5$

Equation of a line passing through the point:

$y-y_1=m(x-x_1)$

$$y-(-5)=-\frac{2}{3} (x-(-5))$

$$y+5=-\frac{2}{3} (x+5)$

$$y+5=-\frac{2}{3} x-\frac{10}{3}$

Subtract 15 from both sides of the equation.

$$y+5-5=-\frac{2}{3} x-\frac{10}{3}-5$

$$y=-\frac{2}{3} x-\frac{25}{3}$

Standard form for the equation of the line is

$$y=-\frac{2}{3} x-\frac{25}{3}$

7 0

3 years ago

The Scott family is trying to save as much money as possible. One way to cut back on the money they spend is by finding deals wh

avanturin [10]

Answer:

Unit price of strawberries at Grocery Mart is $ 1.495 or 150 pennies

Unit price of strawberries at Baldwin Hills Market is $ 1.33 or 133 pennies.

Step-by-step explanation:

1 dollar = 100 pennies

Given:

Cost of 2 pounds of strawberries at Grocery Mart = $ 2.99

Cost of 3 pounds of strawberries at Baldwin Hills Market = $3.99

∵ Cost of 2 pounds of strawberries at Grocery Mart = $ 2.99

∴ Cost of 1 pound of strawberries at Grocery Mart = $\frac{2.99}{2}=\$1.495=1.495\times 100\approx 150\textrm{ pennies}$

∵ Cost of 3 pounds of strawberries at Baldwin Hills Market = $3.99

Cost of 1 pound of strawberries at Baldwin Hills Market = $\frac{3.99}{3}=\$1.33= 1.33\times 100 = 133\textrm{ pennies}$

Therefore, the unit price of strawberries at each grocery store is the cost of 1 pound of strawberries. So, unit rate at Grocery Mart is 150 pennies and at Baldwin Hills Market is 133 pennies.

7 0

3 years ago

HELP WILL GIVE BRAINLIEST

Ganezh [65]

Answer:

2 boom

Step-by-step explanation:

2

4 0

2 years ago

Read 2 more answers

Write an equation for (-1,-2),(-3,-4)

Marina86 [1]

Answer:

y=x+1

Step-by-step explanation:

First find the slope by subtracting the y values from both points and dividing it by the subtraction of the x values from both points:

-4--2/ -3--1= -2/-2= 1

so the slope is 1

Now find the y-intercept by plugging in the x and y from one of the points into the equation y=x+b

-3=-4+b

1=b

now plug the slope and y intercept in:

y=x+1

hope this helps :D

7 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago