Find the p-value in a test of the claim that the mean College Algebra final exam score of engineering majors equal to 88, give
n that the test statistic is zequals1.50.
1 answer:
Answer: 0.9332.
Step-by-step explanation:
Claim : College Algebra final exam score of engineering majors equal to 88.
Given that : The test statistic is z equals to 1.50.
To find the p-value (Probability value), we use standard normal distribution table, and search the p-value corresponds to the z-score.
In a Standard Normal Distribution Table below, the p-value corresponds z equals 1.5 is 0.9332.
Hence, the p-value is 0.9332.
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Answer:
- 103.7
Step-by-step explanation:
Given:
Focal length of the eyepiece, f = 2.0 cm
Focal length of the objective lens, f' = 0.50 cm
Separation for minimum eyestrain = 6,0 cm
Image distance, v = - 25 cm
Now, from the lens formula,
here, u is the object distance
on substituting the respective values, we get
or
u = 1.852 cm
also, the separation is adjusted for minimum eyestrain,
therefore, image distance for the objective lens, v' = 6 - 1.852 = 4.148 cm
Now, for the objective lens
using the lens formula, we get
Here, u' is the distance between the physical object and objective lens
or
u' = 0.568 cm
Thus,
Magnification, m =
or
m =
or
m = - 103.7
One way is to just expand it by using binomial theorem
or to use pascal's triangle
ok so
to find the nth term of a binomial, (a-b). where the binomial is to the r power you do
n-1=k
rCk times
and rCk=
so
4th term
4-1=3
6 is exponent
6C3
=
=
=
the 4th term is
or to use pascal's triangle
ok so
to find the nth term of a binomial, (a-b). where the binomial is to the r power you do
n-1=k
rCk times
and rCk=
so
4th term
4-1=3
6 is exponent
6C3
the 4th term is