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3 years ago

If the APR of a savings account is 5.3% and interest is compounded quarterly,

Mathematics

1 answer:

CaHeK987 [17]3 years ago

4 0

Answer:

5.41%

Step-by-step explanation:

Let us assume that x amount is invested in a savings account with APR 5.3% and the interest is compounded quarterly.

Then the quarterly percentage rate is $\frac{5.3}{4} =1.325$ %.

Therefore, the amount x will become after one year

$x[1+ \frac{1.325}{100} ]^{4} = 1.0541x$

Therefore, the annual percentage yeild will be $\frac{(1.0541x - x) \times 100}{x}$ % = 5.41%. ( Answer )

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Is it true that the order when dividing 3 real numbers does not affect the answer

Jobisdone [24]

No, it is not true

Lets do an example:

4 divided by 2 divided by 1 equals 2, while 2 divided by 1 divided by 4 equals 0.5

8 0

3 years ago

You start hiking at an elevation that is 80 meters below base camp.

Arte-miy333 [17]

Answer:

You are now 38 m below base camp.

Step-by-step explanation:

Consider the provided information.

You start hiking at an elevation that is 80 meters below base camp.

Now your initial location is 80 m below base camp, that can be represents as: -80

Now you increase your elevation by 42.

So you go up by 42.

In other words, you get the equation -80+42 = -38.

Since a negative value is below the base camp, this means that you are now 38 m below base camp.

6 0

3 years ago

Solve 250 ÷ 5 ÷ 10 making sure to divide in the proper order.

Pavlova-9 [17]

It would be the letter A.

I hope this helps! <3

8 0

3 years ago

Read 2 more answers

What is the area to a 2 3/4 inch square?

Vinvika [58]

Since every side of a square is the same length, and the formula to find the area is bh you would just do 2.75²

2.75×2.75=7.5625≈7.56

the answer is the area of the square is approximately 7.56u²

5 0

3 years ago

15 points!!! GEOMETRY help please!!<br> Questions attached!

dolphi86 [110]

3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

$x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o$

$Answer:\ \boxed{47^o}$

4.
Look at the picture.

Use Pythagorean theorem:

$x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8$

$Used:\ (a+b)^2=a^2+2ab+b^2$

$Answer:\ \boxed{4.8\ units}$

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}$

We have: $OP:\ y=-\dfrac{3}{2}x+b$

Now, we must find the slope of the line perpendicular to the line OP.
We know:

$k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1$

therefore

$-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}$

So. We have the answer! :)

$Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}$

6 0

3 years ago