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Evgesh-ka [11]
3 years ago
7

-10v+3 Name the polynomial by degree and the number of terms

Mathematics
1 answer:
Liula [17]3 years ago
6 0
Terms: Binomial
Degree: Linear
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What's the geometric mean of these two numbers? 8.5 and 12.4
Strike441 [17]
(8.5*12.4)^(1/2)=10.266

In general the geometric mean is (ab)^(1/2), (abc)^(1/3), (abcd)^(1/4), etc

The nth root of the product of n elements.
7 0
3 years ago
The value of a car with an initial purchase price of $15,250 depreciates by 16% per year. How much is the car worth after 6 year
Scrat [10]

Answer:

$13842.43

Step-by-step explanation:

Given data

Value of car=$15,250

Rate of depreciation= 16%

Time = 6 years

We can use the exponential function below to model the value of the car after 6 years

v(t)= a(r)^x

But r= 1-0.016----------Because the value is depreciating

a=15,250  

r=0.016  

x=6

Substitute

v(t)= 15250(1-0.016)^6

v(t)=  15250(0.984)^6

v(t)=  15250*0.9077

v(t)= $13842.43

Hence the value will be $13842.43 after 6 years

8 0
2 years ago
One reading an Antarctic research station showed that the temperature was -35 degrees Celsius what is this temperature in degree
Musya8 [376]
It is very simple it would be positive but would remain 35
4 0
3 years ago
Help please!! i will mark you brainliest
Gre4nikov [31]

Answer:

the equation is (y-3)^2 = 4(x+3)

8 0
3 years ago
Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3
nlexa [21]

Answer:

(x,y) = (5,-6)

Step-by-step explanation:

\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\

                     ~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)

\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\

\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5

y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6

\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)

7 0
1 year ago
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