21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Answer:
4, 3.5, 4.5, 4.2, and 3.7
Step-by-step explanation:
It's math
Answer:
X=½ or 3
Step-by-step explanation:
0=2x²-7x+3
0=(2x-1)(x-3)
0=2x-1 or 0=x-3
1=2x or 3=x
½=x
Answer:
0.875
Step-by-step explanation:
Answer:
V = pi x radius x 2 x height OR pi x diameter x height
Hope that helps!
