Answer:
t^-12
Step-by-step explanation:
you multiply the -2 and 6.
I would subtract the 2nd from the first one
so -4x - -2x = -2x
4y - 4y = 0
-20 - -2 = -18
-2x = -18
now I would divide that by -2 to get the value for x
so no we have x = 9
now you just have to substitute that into one of the equations and simplify to get y
-2 X 9 + 4y = -2
-18 + 4y = -2
4y =16
y = 4
y - y₁ = m(x - x₁)
y - 1 = 1³/₅(x - 2) Point - Slope Form
y - 1 = 1³/₅(x) - 1³/₅(2)
y - 1 = 1³/₅x - 3¹/₅
+ 1 + 1
y = 1³/₅x - 2¹/₅ Slope - Intercept Form
-1³/₅x - y = 1³/₅x - 1³/₅x - 2¹/₅
-1³/₅x - y = -2¹/₅
-1(-1³/₅x - y) = -1(-2¹/₅)
-1(-1³/₅x) + 1(y) = 2¹/₅
1³/₅x - y = 2¹/₅ Standard Form
1³/₅(0) - y = 2¹/₅
0 - y = 2¹/₅
-y = 2¹/₅
-1 -1
y = -2¹/₅ Y - Intercept
(x, y) = (0, -2¹/₅)
Answer:
I think that the rectangles,L's and I'm not sure about the other ones
Answer:
x=-2,2
Step-by-step explanation:
Since this is a quadratic equation, -2 or 2 could be the possible answer
Steps
$3x^2=12$
$\mathrm{Divide\:both\:sides\:by\:}3$
$\frac{3x^2}{3}=\frac{12}{3}$
$\mathrm{Simplify}$
$x^2=4$
$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$
$x=\sqrt{4},\:x=-\sqrt{4}$
Show Steps
$\sqrt{4}=2$
Show Steps
$-\sqrt{4}=-2$
$x=2,\:x=-2$
