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Scilla [17]
3 years ago
10

Find the product. (4t+na) (t - 2na)

Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0

Answer:

4t^2 - 8tna + nat - 2 n^2 a^2

Step-by-step explanation:

Dudjdkdjejdnkdhdbd

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Read each relationship and decide whether its graph would be continuous or discrete
Afina-wow [57]
The ones which are discrete would have answers like 1234 and would not have any decimal answers so you can’t have half a student or half a chair there for those of the two that are discrete
5 0
4 years ago
Triangle XYZ is translated by the rule (x + 1, y − 1) and then dilated by a scale factor of 4 centered at the origin. Which stat
Doss [256]

Answer:

D) Segment YZ and segment Y"Z" are proportional after the dilation and congruent after the translation.

Step-by-step explanation:

After a dilation, a figure remains proportional because its angles and betweenness of points remain the same. After a translation, the image stays congruent to the pre-image.

3 0
3 years ago
Read 2 more answers
Do patterns excist in every thing around us ? why ,why not?<br><br>​
vichka [17]

Answer:

<em>Patterns are important because <u>they offer visual clues to an underlying order</u>. If you can unlock a pattern, then you have the ability to alter or shape it in order to achieve some effect. Patterns can also be used as a template that will enable one to quickly analyze a situation and understand how it works.</em>

6 0
2 years ago
Log In a survey of a town, 63% of residents own a car, 20% of residents own a truck, and 4% of residents own both a car and a tr
yan [13]

Answer:

6%

Step-by-step explanation:

Let T= truck

C= Car

We are looking for the probability that someone owns a truck given that they own a car

or

P(T|C)

The conditional probability formula is as follows:

P(T|C)=(T∩C)/C

plugging in numbers..

.04/.63=6.3492% which rounds to 6%

4 0
3 years ago
Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas
Vitek1552 [10]

Answer:

a)

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )

a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

3 0
3 years ago
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