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wolverine [178]
3 years ago
11

G(x) = -3/2x-9, if G(x) = -48, find x

Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

x=26

Step-by-step explanation:

first rewrite the problem since u know that G(x)=-48

-48=-3/2x-9

second you want to add the 9 to -48 which gives u -39

-39=-3/2x

third you want to times the reciprocal so it would be

-2/3 times -39/1

u can cross out the negatives and turn them into a positive

fourth you can cross cancel 3 and 39 which now the problem looks like this

2/1 times 13/1

which you would times 2 and 13 which your answer would be

26

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Check the picture below.

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\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{using this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \begin{cases} h=-3\\ k=-\frac{3}{2}\\[0.7em] p=-\frac{7}{2} \end{cases}\implies 4\left( -\cfrac{7}{2} \right)\left[ y-\left(-\cfrac{3}{2} \right) \right]=\left[ x-\left( -3 \right) \right]^2 \\\\\\ -14\left( y+\cfrac{3}{2} \right)=(x+3)^2\implies y+\cfrac{3}{2} =-\cfrac{(x+3)^2}{14} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{14}(x+3)^2-\cfrac{3}{2}~\hfill

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