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konstantin123 [22]
3 years ago
9

in the school cafeteria students chose their lunch from 3 sandwiches, 3 soups, 4 salads, and 2 drinks. how many different lunche

s are possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink?
Mathematics
1 answer:
Vesna [10]3 years ago
7 0

Answer:

Answer:

3

×

3

×

4

×

2

=

72

Explanation:

Let's look at the 3 sandwiches and 3 soups first and then expand the calculation. There are 9 ways I can have one of the sandwiches and 1 of the soups:

⎛

⎜

⎜

⎜

⎜

⎝

0

Soup 1

Soup 2

Soup 3

Sandwich 1

1

2

3

Sandwich 2

4

5

6

Sandwich 3

7

8

9

⎞

⎟

⎟

⎟

⎟

⎠

And so we can see that we multiply the number of sandwiches and the number of soups to get the total number of ways to get one of each.

The same works for more categories of choices, and so we multiply the 3 sandwiches, the 3 soups, 4 salads, and 2 drinks to get:

3

×

3

×

4

×

2

=

72


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Helen [10]

The solutions of the equations for x are given as follows:

a. x = 36.

b. x = 15.

<h3>What is the solution for item a?</h3>

The equation for item a is given by:

x/3 - 5 = 7

Isolating x, we have that:

x/3 = 12

x = 3 x 12

x = 36.

<h3>What is the solution for item b?</h3>

The equation for item b is given by:

x/2 - 5 = 2.5

Isolating x, we have that:

x/2 = 7.5

x = 7.5 x 2

x = 15.

Hence the solutions are:

a. x = 36.

b. x = 15.

More can be learned about equations at brainly.com/question/25537936

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motikmotik

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Arlecino [84]

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Step-by-step explanation:

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Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Valentines Day! :-)  

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victus00 [196]

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Step-by-step explanation: Given expression (5.63 \times 10^5) \times 5,600,000.

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Therefore, (5.63 \times 10^5) \times 5,600,000 =(5.63 \times 10^5) \times (5.6 \times 10^6).

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Therefore,

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