Step-by-step explanation:
multiply 2 with the bracket numbers
6x+16=0
6x= - 16
x=-16/6
x= - 8/3
6 - 3 = 3
-2 - (-9) = 7
(3 , 7)
Gcf first
21y(y+5)
solutions are 0,-5
For this case we have the following equation:
h = -16t2 + 32t + 6
Deriving we have:
h '= -32t + 32
Equaling to zero:
-32t + 32 = 0
We clear the time:
t = 32/32
t = 1 s
We are now looking for the maximum height:
h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
h (1) = 22 feet
Answer:
The ball reaches its maximum height in:
t = 1 s
The ball's maximum height is:
h (1) = 22 feet
option: 22 ft, 1 s
7% Of 9000 is 630. Then subtract 630 from 9000. So your answer becomes 8370.
