If the runner moves at 6 miles per hour for 2 hours before the cyclist starts, the runner has a 12 mile lead at the beginning. If the cyclist is going at 16 miles per hour, he is overtaking the runner at 10 miles per hour, because 16-6=10. Then, the amount of time it takes the cyclist to go 2 miles in 10 miles per hour is the answer. this is 1/5 of an hour, or 12 minutes.
Answers
9(x + y)
(7 - a)(b)
The Distributive Property is used in algebraic expressions to multiply a
single term and two or more terms which are inside a set of parentheses.
In the case of x(2y), there is only
one term inside the parenthesis
In the case of 9(x ∙ y), the distributive
property is not used because (x ∙ y) = xy which means only one term will be
multiplied by the term outside the parenthesis (9)
In the case of 9(x + y), the distributive
property is used because the two terms in the parenthesis (x and y) will be
multiplied by the term outside the parenthesis (9)
9(x + y) = 9*x + 9*y (by applying the distributive property)
In the case of (7 ∙ a)(b), the distributive
property is not used because (7 ∙ a) = 7a which means only one term will be
multiplied by the term outside the parenthesis (b)
In the case of (7 - a)(b), the distributive
property is used because the two terms in the parenthesis (7 and -a) will be
multiplied by the term outside the parenthesis (b)
(7 - a)(b) = 7*b - a*b (by applying the distributive
property)
In the case of (2 ∙ x) ∙ y, the distributive
property is not used because (2 ∙ x) = 2x which means only one term will be
multiplied by the term outside the parenthesis (y)
Answer: 500
Step-by-step explanation:
The reason why it's 500 because it's already been rounded. 500 stays as 500 bc numbers 4 and below goes down to 0 when rounding. When rounding 0-4 with just the ones place it stays the same.
Answer:
dh/dt = 3/25π m/min
Step-by-step explanation:
Radius = 5m
Rate (dV/dt) = 3 cm^3 / min
Leaking rate = 1 cm^3 / min
Volume = πr^2h
Volume = π(5)^2h
V= 25πh
Differentiate volume implicitly with respect to time
dV/dt = 3 cm^3/min
3 = 25π(dh/dt)
dh/dt = 3 m^3/min /25πm^2
dh/dt = 3/25πm/min
