1/6 cup of raisins. this is because 2/3 = 4/6 therefore you have 1 5/6 cups in total before the raisins are added
Type I error says that we suppose that the null hypothesis exists rejected when in reality the null hypothesis was actually true.
Type II error says that we suppose that the null hypothesis exists taken when in fact the null hypothesis stood actually false.
<h3>
What is
Type I error and Type II error?</h3>
In statistics, a Type I error exists as a false positive conclusion, while a Type II error exists as a false negative conclusion.
Making a statistical conclusion still applies uncertainties, so the risks of creating these errors exist unavoidable in hypothesis testing.
The probability of creating a Type I error exists at the significance level, or alpha (α), while the probability of making a Type II error exists at beta (β). These risks can be minimized through careful planning in your analysis design.
Examples of Type I and Type II error
- Type I error (false positive): the testing effect says you have coronavirus, but you actually don’t.
- Type II error (false negative): the test outcome says you don’t have coronavirus, but you actually do.
To learn more about Type I and Type II error refer to:
brainly.com/question/17111420
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Hi!
Let's put the values in the equation.
10 · 5 + 16 ÷ 4 = ?
Using PEMDAS...
Multiplication
50 + 16 ÷ 4 = ?
Division
50 + 4 = ?
Addition
54
The answer is 54
Hope this helps! :)
Answer: x=−1 and y=4
Step-by-step explanation:
Answer:
20 nickels and 26 dimes
Step-by-step explanation:
- She has $3.60 in nickels and dimes
- a nickel is $0.05 and a dime is $0.10
- let n be the number of nickels and d be the number of dimes
- thus the first equation is 3.6 = 0.05n +0.1d
- If she has 46 coins then n + d = 46
- then n = 46 - d
- sub n = 46 - d into 3.6 = 0.05n +0.1d
- 3.6 = 0.05(46 - d) + 0.1d
- 3.6 = 2.3 -0.05d+0.1d
- 1.3 = 0.05d
- 26 = d
- sub d = 26 into n+d=46
- n+26=46
- n=20
- Check by subbing n=20 and d=26 into 0.05n +0.1d
- 0.05(20) +0.1(26)
- 1+2.6 = 3.6
