Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two

Mathematics

1 answer:

telo118 [61]3 years ago

8 0

Answer:

8 cm , 9cm

Step-by-step explanation:

sum of any two sides >third side

difference of any two sides<third side

only 8 cm and 9 cm satisfies it

8+9=17>13

9-8=1<13

You might be interested in

A school library charges a fine of 5 cents on the first day a book is overdue, then doubles the amount owed each day until payme

andrey2020 [161]

Answer:

Jada's book was overdue by 1 more day than Juan's book.

...................

6 0

3 years ago

Find the values of x and y for the isosceles trapezoid

butalik [34]

<h3>Answer:</h3>

x = 15
y = 3

<h3>Step-by-step explanation:</h3>

If the trapezoid is isosceles, angles A and C are supplementary, so ...

... (4x+4) +(7x+11) = 180

... 11x +15 = 180 . . . . . . collect terms

... 11x = 165 . . . . . . . . . subtract 15

... x = 15 . . . . . . . . . . . . divide by the coefficient of x

And angles C and E are congruent.

... 4·15 +4 = 21y +1

... 63 = 21y . . . . . subtract 1

... 3 = y . . . . . . . . divide by the coefficient of y

4 0

3 years ago

Select the relations that are functions.

Arlecino [84]

Answer:

Depending on how the input of each function defined,

The first choice $\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace$ ,
The third choice $\left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace$
The fourth choice $\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace$

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

be defined for all elements in the domain, and
map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element $a$ from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be $\lbrace a,\, 6, \, C\rbrace$ . Similarly, the domain for the third and fourth relations should be $\lbrace 1,\, 2, \, 3\rbrace$ and $\lbrace a,\, b, \, c\rbrace$