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sveticcg [70]
3 years ago
11

−4(m+6)=−8 plz answer

Mathematics
1 answer:
dangina [55]3 years ago
5 0

Answer:Divide both sides by the numeric factor on the left side, then solve.

m

=

−

4

Step-by-step explanation:

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The perimeter of a 14 ft , 8 ft rectangle
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What is the length of the arc if: 11. r=10 n=20 A15(pi)/ 7 B13(pi)/ 5 C16(pi)/ 2 D11(pi)/ 4 E 10(pi)/ 9 F 9(pi)/ 4 12. r=3 n=6 A
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Step-by-step explanation:

The formula for arc length [for the angle in degrees] is:

L = 2\pi r \left(\dfrac{n}{360}\right)

here,

n = degrees

r = radius

using this we'll solve all the parts:

r = 10, n = 20:

L = 2\pi r \left(\dfrac{n}{360}\right)

L = 2\pi (10) \left(\dfrac{20}{360}\right)

from here, it is just simplification:

2 and 360 can be resolved: 360 divided by 2 = 180

L = \pi (10) \left(\dfrac{20}{180}\right)

10 and 180 can be resolved: 180 divided by 10 = 18

L = \pi \left(\dfrac{20}{18}\right)

finally, both 20 and 18 are multiples of 2 and can be resolved:

L = \pi \left(\dfrac{10}{9}\right)

L = \dfrac{10\pi}{9} Option (E)

r=3, n=6:

L = 2\pi r \left(\dfrac{n}{360}\right)

L = 2\pi (3) \left(\dfrac{6}{360}\right)

L = \dfrac{\pi}{10} Option (D)

r=4 n=7

L = 2\pi r \left(\dfrac{n}{360}\right)

L = 2\pi (4) \left(\dfrac{7}{360}\right)

L = \dfrac{7\pi}{45} Option (C)

r=2 n=x

L = 2\pi r \left(\dfrac{n}{360}\right)

L = 2\pi (2) \left(\dfrac{x}{360}\right)

L = \dfrac{x\pi}{90} Option (D)

r=y n=x

L = 2\pi r \left(\dfrac{n}{360}\right)

L = 2\pi (y) \left(\dfrac{x}{360}\right)

L = \dfrac{xy\pi}{180} Option (E)

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3 years ago
The sets of numbers 3, 4, 5 and 8, 15, 17 are Pythagorean triples. Use what you know about the Pythagorean Theorem and explain o
konstantin123 [22]

Answer:

When we have 3 numbers, like:

a, b and c.

Such that:

a < b < c.

These numbers are a Pythagorean triplet if the sum of the squares of the two smaller numbers, is equal to the square of the larger number:

a^2 + b^2 = c^2

This is equivalent to the Pythagorean Theorem, where the sum of the squares of the cathetus is equal to the hypotenuse squared.

Now that we know this, we can check if the given sets are Pythagorean triples.

1)  3, 4, 5

Here we must have that:

3^2 + 4^2 = 5^2

solving the left side we get:

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and the right side:

5^2 = 25

Then we have the same in both sides, this means that these are Pythagorean triples.

2) 8, 15, 17

We must have that:

8^2 + 15^2 = 17^2

Solving the left side we have:

8^2 + 15^2 = 64 + 225 = 289

And in the right side we have:

17^2 = 17*17 = 289

So again, we have the same result in both sides, which means that these numbers are Pythagorean triples

4 0
2 years ago
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