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Afina-wow [57]
3 years ago
13

In a triangle ABC, AB=AC and ˂A=70°, find the angles,˂B and ˂C

Mathematics
1 answer:
aleksklad [387]3 years ago
4 0

Answer:

m<B = m<C = 55

Step-by-step explanation:

Since those two sides are congruent, the base angles are congruent.

m<B = m<C = x

m<A + m<B + m<C = 180

70 + x + x = 180

2x + 70 = 180

2x = 110

x = 55

m<B = m<C = 55

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There is no figure of the triangle, all that I know about it is
<span>cos Pi/6 =√3/2</span>
7 0
3 years ago
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alukav5142 [94]

Step-by-step explanation:

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8 0
2 years ago
Which equation represents an inverse variation?
Sphinxa [80]

Answer: Choice C) y = 30/x

Inverse variation equations are of the form y = k/x. In this case, k = 30. We can rearrange the format to get x*y = k after multiplying both sides by x. So y = 30/x can be turned into x*y = 30.

7 0
3 years ago
Of the students in your class, 12% are left-handed. What fraction of the students are left-handed? Are there more right-handed o
kvv77 [185]
The left-handed students
12% are left handed, percent means per hundred. Change percent into per 100.
12% = \dfrac{12}{100}

Then simplify the fraction by dividing the numerator and denominator by 4
\dfrac{12}{100}
= \dfrac{12:4}{100:4}
= \dfrac{3}{25}
This is the fraction showing the proportion of the left-handed students

The right-handed students
Determine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 - \dfrac{3}{25}

Equalize the denominator to 25
\dfrac{25}{25} - \dfrac{3}{25}

Simplify
\dfrac{21}{25}
This is the proportion of the right-handed students

<span>Are there more right-handed or left-handed students?
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4 0
3 years ago
John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs
mezya [45]

Answer:

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The number of Green Beans can used =   16 cans

Step-by-step explanation:

The ratio of Pumpkin to Green Beans =  3 :  1

So, for every 3 can of Pumpkin, 1 can of green beans is used.

Now, the total number of  John  wants to use = 64

Let us assume the common factor in the ratio is m.

⇒ The number of Pumpkin can used  = 3 m

The number of Green Beans can used = 1 m = m

So, the Total cans used = Number of (Pumpkin + Green Beans) can

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or, 4 m =  64

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Hence, The number of Pumpkin can used  = 3 m = 3 x 16 = 48 cans

The number of Green Beans can used = m =  16 cans

3 0
3 years ago
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