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3 years ago

2H2 + O2 → 2H2O

Chemistry

2 answers:

sveta [45]3 years ago

6 0

Answer : The number of moles of $O_2$ required are 0.835 moles.

Explanation : Given,

Moles of $H_2$ = 1.67 moles

The given balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

By the stoichiometry we can say that, 2 moles of hydrogen gas react with 1 mole of oxygen gas to give 2 moles of water as a product.

From the balanced reaction we conclude that,

As, 2 moles of $H_2$ react with 1 mole of $O_2$

So, 1.67 moles of $H_2$ react with $\frac{1.67}{2}=0.835$ mole of $O_2$

Therefore, the number of moles of $O_2$ required are 0.835 moles.

Bogdan [553]3 years ago

5 0

Mole ratio:

2 H2 + O2 = 2 H2O

2 mol H2 ---------- 1 mol O2
1.67 mol H2 ------ ??

1.67 x 1 / 2 => 0.835 moles of O2

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Chemical reactions involving only liquids will be influenced by ALL of the following EXCEPT: c) size of reactant particles d) pressure of the system.

Reason:
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From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle.

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Read 2 more answers

How much pure acid is in 520 milliliters of a 13 % solution?

Liono4ka [1.6K]

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3 years ago

Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

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likoan [24]

Answer:

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