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scZoUnD [109]
4 years ago
14

why is uranium 235 the most commonly used isotope for nuclear fission in current uses in nuclear power generation?

Chemistry
1 answer:
Pachacha [2.7K]4 years ago
6 0
This is because U-235 decays naturally by a process known as alpha radiation. This means that it releases an alpha particle (two neutrons and two protons connected together).
Another reason that U-235 is ideal for producing nuclear power is that unlike most materials, U-235 can undergo induced fission. When a free neutron collides with a U-235 nucleus, the nucleus will usually capture the neutron and split extremely quickly. The splitting of a single U-235 atom can release roughly 200 MeV (million electron volts).
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What effect does thermal energy have on the rate of chemical reactions?
Zielflug [23.3K]

Answer:

The temperature, however, greatly affects the rate of a chemical reaction. As you heat a substance, its molecules move faster and are more likely to react. Some reactants even require some heat to initiate a reaction. Reaction Rates and Temperature

Explanation:

5 0
3 years ago
Read 2 more answers
A solid mixture consists of 47.6g of KNO3 (potassium nitrate) and 8.4g of K2SO4 (potassium sulfate). The mixture is added to 130
IgorLugansk [536]

<u>Answer:</u> No crystals of potassium sulfate will be seen at 0°C for the given amount.

<u>Explanation:</u>

We are given:

Mass of potassium nitrate = 47.6 g

Mass of potassium sulfate = 8.4 g

Mass of water = 130. g

Solubility of potassium sulfate in water at 0°C = 7.4 g/100 g

This means that 7.4 grams of potassium sulfate is soluble in 100 grams of water

Applying unitary method:

In 100 grams of water, the amount of potassium sulfate dissolved is 7.4 grams

So, in 130 grams of water, the amount of potassium sulfate dissolved will be \frac{7.4}{100}\times 130=9.62g

As, the soluble amount is greater than the given amount of potassium sulfate

This means that, all of potassium sulfate will be dissolved.

Hence, no crystals of potassium sulfate will be seen at 0°C for the given amount.

7 0
3 years ago
A solution that contains the maximum amount of solute that is soluble at a given temperature is said to be —
solniwko [45]

Answer: Saturated

A solution that contains the maximum amount of solute that is soluble at a given temperature is said to be saturated.

Explanation:

A Saturated solution is one that contains as much (i.e maximum) solute as it can dissolve at that temperature in the presence of undissolved solute particles.

For instance: if a given volume of water can only dissolve a certain amount of salt in it at room temperature, then, more salt added will not dissolve.

Thus, making the solution saturated.

5 0
3 years ago
It take 38.70cm³ of 1.90m NaoH to neutralize 10.30cm³ of H2so4 in a battery, calculate the molar concentration of H2so4
zlopas [31]

Answer:

M_{acid}=3.57M

Explanation:

Hello there!

In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:

2M_{acid}V_{acid}=M_{base}V_{base}

In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:

M_{acid}=\frac{M_{base}V_{base}}{2V_{acid}}

Thus, we plug in the given data to obtain:

M_{acid}=\frac{38.70cm^3*1.90M}{2(10.30cm^3)} \\\\M_{acid}=3.57M

Best regards!

8 0
3 years ago
A 150 W electric heater operates for 12.0 min to heat an ideal gas in a cylinder. During this time, the gas expands from 3.00 L
Brut [27]

<u>Answer:</u> The change in internal energy of the gas is 108.835 kJ

<u>Explanation:</u>

To calculate the work done for reversible expansion process, we use the equation:

W=P\Delta V=-P(V_2-V_1)

where,

W = work done

P = pressure = 1.03 atm

V_1 = initial volume = 3.00 L

V_2 = final volume = 11.0 L

Putting values in above equation, we get:

W=-(1.03)\times (11.0-3.00)=8.24L.atm=834.9J=0.835kJ     (Conversion factor:  1 L. atm = 101.325 J)

Calculating the heat from power:

Q=P\times t

where,

Q = heat required

P = power = 150 W

t =  time = 12 min = 720 s       (Conversion factor:  1 min = 60 s)

Putting values in above equation:

Q=150\times 720=108000J=108kJ

The equation for first law of thermodynamics follows:

Q=dU+W

where,

Q = total amount of heat required = 108 kJ

dU = Change in internal energy = ?

W = work done  = -0.835 kJ

Putting values in above equation, we get:

108kJ=dU+(-0.835)\\\\dU=(108+0.835)=108.835kJ

Hence, the change in internal energy of the gas is 108.835 kJ

7 0
4 years ago
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