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Margaret [11]
4 years ago
5

PLZ HELP IM VERY DESPERATE

Mathematics
1 answer:
VikaD [51]4 years ago
3 0
The answers are x=3 and PS=5.5
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In which quadrant is the point (-2,3) located? Quadrant I Quadrant II Quadrant III Quadrant IV
musickatia [10]

Answer:

Quadrant 2

Step-by-step explanation:

Quadrant 2 has a negative x-axis and a positive y-axis

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Jessica had 111 dollars to spend on 8 books.
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Answer= 12
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3 years ago
HELP!!
Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

(x,y)\rightarrow (-x,y)

It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2:

If polygon MNOPQ is translated 3 units right and 5 units down, then

(x,y)\rightarrow (x+3,y-5)

M(-2,8)\rightarrow V(-2+3,8-5)=V(1,3)

N(-4,12)\rightarrow W(-4+3,12-5)=W(-1,7)

O(-10,12)\rightarrow X(-10+3,12-5)=X(-7,7)

P(-8,8)\rightarrow Y(-8+3,8-5)=Y(-5,3)

Q(-6,6)\rightarrow Z(-6+3,6-5)=Z(-3,1)

Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

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3 years ago
PLEASE HELP ME, I REALLY NEED A GOOD GRADE. TO WHOEVER GETS IT I WILL MAKE YOU BRAINLIST!
Aliun [14]

Answer:

(5x - 7) + 9x

Step-by-step explanation:

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3 years ago
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How do i find the perimeter and area?
ch4aika [34]

Answer:

for perimeter you add all the sides and for area you multiply

Step-by-step explanation:

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