Answer: (b) exactly one plane contains a given line and a point not on the line.
Step-by-step explanation: The basic postulates of geometry are very-well known to all of us. For example-
(i) The intersection of two lines determines a point,
(ii) Two parallel lines give result to a plane,
(iii) A line and a point not on the line determines a plane, etc...
Thus, with the help of the third point, we can easily arrive at the conclusion that a given line and a point not lying on the line is contained in a plane. For example- see the attached figure, AB is a line and P is any point not on the line. They both contained in the plane ABC.
Hence, the correct option is (b).
You can solve this by multiplying each numerator by the answer choices and trying to divide them. I can't get the fraction maker to work at the moment, so I'll write the calculations on a separate attachment.
As you can see, the only choice that works to eliminate both fractions is the fourth choice,
50x.
Answer:
6^21 = B
Step-by-step explanation:
![[6^{7} ]^{3} \\(6)^7^*^3\\6 ^{21} \\](https://tex.z-dn.net/?f=%5B6%5E%7B7%7D%20%5D%5E%7B3%7D%20%5C%5C%286%29%5E7%5E%2A%5E3%5C%5C6%20%5E%7B21%7D%20%5C%5C)
We substitute the given into the equation
given: a=-1, b=2, c=

=(

-1
=

-1
=

-1
=

-1
to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:

=-2.5
Equation=-2.5-1=-3.5
OR Common Denominator:
=


×

(denominator should be -2=common)
=

+

=

which also = to -3.5