Answer:
2
Step-by-step explanation:
1/8 2/8 3/8 4/8 5/8 6/8 7/8 8/8
8/8-6/8=2/8
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
<span>it divides two sides of a triangle equally. The midpoint of a side divides the side into two equal segments.</span>
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Answer:
a(n) = 20*2.5^(n - 1)
Step-by-step explanation:
Note that 50 is 2.5 times 20, and that 125 is 2.5 times 50. Thus the common factor is 2.5. The formula for the nth term is
a(n) = a(1)*r^(n - 1) => a(n) = 20*2.5^(n - 1)
