Question

Find the shorter base of a trapezoid if the trapezoid's area is 52, its altitude is 8, and its longer basis 10.

Answer 1

Answer:

The shorter base is 3

Step-by-step explanation:

$a = \frac{(b1 + b2)}{2} \times h$

$52 = \frac{(10 + b2)}{2} \times 8$

$b2 = 3$