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ser-zykov [4K]
3 years ago
12

Milk is delivered to a chain of regional supermarkets once a week. If the weekly volume of sales in thousands of gallons is a ra

ndom variable with probability density function f(x) = 7(1 – x)^6 for 0 < x < 1 0 otherwise How much milk must the chain of supermarkets order for each delivery so that the probability of the supply being exhausted in a given week is just 2%?
Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

The chain of supermarkets must order 428.1 gallons of milk.

Step-by-step explanation:

Let's define the random variable X.

X : ''Weekly volume of sales in thousands of gallons''

X is a continuous random variable.

The probability density function for X is

f(x)=7(1-x)^{6} when 0 < x < 1

f(x)=0   Otherwise.

Let's denote as ''a'' to the quantity of milk for the question.

We are looking for :

P(X>a)=0.02

P(X>a)=\int\limits^1_a {f(x)} \, dx

P(X>a)=\int\limits^1_a {7(1-x)^{6}} \, dx

P(X>a)=(1-a)^{7}

(1-a)^{7}=0.02

a=1-\sqrt[7]{0.02}

a=0.4281

a is in thousands of gallons, therefore the chain of supermarkets must order  

428.1 gallons of milk in order to satisfy the question.

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Step-by-step explanation:

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I can eyeball points (1/2, 8), (1,4), (2,1), (3,1/4)


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a) The length of p is 21.4 cm

b) The measure of angle P is 45.6°

<h3>Trigonometry </h3>

From the question, we are to determine the length of p

From the <em>Pythagorean theorem</em>, we can write that

30² = 21² + p²

p² = 30² - 21²

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p = √459

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∴ The length of p is 21.4 cm

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What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

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So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

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