"Given a block of frozen salt water, how could you separate

1 answer:

4 0

Answer: You could put the frozen block of ice on the stove and let it melt and eventually boil out leaving the salt behind

Explanation:

You might be interested in

Is the following sentence true or false? the mass of an object changes with location.

Whitepunk [10]

This is false because it doesn't matter about the mass

6 0

3 years ago

To what extent do covalent compounds conduct electricity?

sertanlavr [38]

The answer is never because there's no electricity

3 0

3 years ago

Read 2 more answers

Write the condensed nd structural formulas as well as the names for all isomers of C3H5Cl3.

Sergio039 [100]

Answer:

1) 1,1,1-trichloropropane

2) 1,1,2-trichloropropane

3) 1,2,2-trichloropropane

4) 1,2,3-trichloropropane

Explanation:

For this question, we must remember that isomers are molecules that have the same formula but different structures. For the formula $C_3H_5Cl_3$ we can draw a linear chain of three carbons and change the position of the chlorine atoms in the carbon chain.

With this in mind, if we put all the chlorine atoms on the same carbon we will get 1,1,1-trichloropropane. If we change an atom from chlorine to carbon 2 we will obtain 1,1,2-trichloropropane. If we move another chlorine atom to carbon two we will get 1,2,2-trichloropropane. Finally, if we put a chlorine atom in each carbon we will obtain 1,2,3-trichloropropane.

See figure one for further explanations

I hope it helps!

4 0

3 years ago

If you are pushing a shopping cart and you start pushing harder , what happens?

olya-2409 [2.1K]

The kinetic energy of the shopping cart increases. This speeds up the energy rate of friction between the wheel and the floor giving off more kinetic energy so the speed rate can increase (depending on how much your pushing it) Hope this helps :)

4 0

3 years ago

Read 2 more answers

A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the te

Monica [59]

You can establish a system of two equation with two variables.

Varibles are:
V1 = volume of the 50% sugar solution
V2 = volumen of the 80% sugar solution

Equations:
Balance of sugar:

Sugar from 50% solution: 0.5*V1
Sugar from 80% solution: 0.8*V2
Sugar in the final solution (mix): 0.6 * 105 = 63

1) 0.5V1 + 0.8V2 = 63

Final volume = volume of 50% solution + volume of 80% solution

2) V1 + V2 = 105

From (2) V1 = 105 - V2

Substitue in (1)

0.5 (105 - V2) + 0.8 V2 = 63

52.5 - 0.5V2 + 0.8V2 = 63

0.3 V2 = 63 - 52.5

0.3 V2 = 10.5

V2 = 10.5/0.3
V2 = 35mL

V1 = 105 - 35 = 70 mL

Answer: 70 mL of the 50% solution and 35 mL of the 80% solution.

5 0

4 years ago