Hi!
The best possible name for this molecule would be: 4 - ethyl - 1 - heptene or 4 - ethylhept - 1 - ene
We always name the molecule with respect to the longest chain (in a branched molecule), taking both atoms of carbon participating in the double bond into account too. In our case, this gives us a 7 Carbon chain - hept
ene - is the suffix that is indicative of the molecule being an alekene.
<em>So we know it is a branched heptene molecule</em>
We add the number where the double bond occurs either before ene, or before heptene as a rule.
<em>Note: We always start with the end of the chain from where the double bond is the closest, and number the carbons accordingly.</em>
The title and position of the branch always comes at the start. In our case the branch is a two carbon chain, and an alkane, so it would be an ethyl branch. This branch occurs at carbon number 4
Hence, the correct names would be:
<em>4 - ethyl - 1 - heptene</em> or <em>4 - ethylhept - 1 - ene</em>
Hope this helps!
Explanation:
The answer is to this question is
60 m/s.
<h2>Acetic Acid + Sodium ethoxide ⇄ Butyric Acid + Sodium Hydroxide</h2>
Explanation:
An ionic equation for the reaction of acetic acid with sodium ethoxide is as follows -
Acetic Acid and Sodium ethanolate (sodium ethoxide)
Butyric Acid and Sodium hydroxide
Hence,
Acetic Acid + Sodium ethoxide ⇄ Butyric Acid + Sodium Hydroxide
⇄ 
- Weak acids and bases have low energy than strong acids and bases.
- The chemical equilibria shift the reaction side with the species having lower energy.
- Given reaction is an acid-base reaction in which the equilibrium favors the starting material that means it will go to the side of the weakest acid that is acetic acid is weaker than butyric acid.
. The energy of shells in a hydrogen atom is calculated by the formula E = -Eo/n^2 where n is any integer, and Eo = 2.179X10^-18 J. So, the energy of a ground state electron in hydrogen is:
E = -2.179X10^-18 J / 1^2 = -2.179X10^-21 kJ
Consequently, to ionize this electron would require the input of 2.179X10^-21 kJ
2. The wavelength of a photon with this energy would be:
Energy = hc/wavelength
wavelength = hc/energy
wavelength = 6.626X10^-34 Js (2.998X10^8 m/s) / 2.179X10^-18 J = 9.116X10^-8 m
Converting to nanometers gives: 91.16 nm
3. Repeat the calculation in 1, but using n=5.
4. Repeat the calculation in 2 using the energy calculated in 3.
