Get rid of negative exponents by remembering that x^-a= 1/x^a.
6^-3= 1/6^3
Evaluate the exponent
6^3= 216
Final answer: 1/216
Answer:
(d) All of the above
Step-by-step explanation:
In order to solve this question we will have to find out which numbers are located in which group (the group of numbers are U, B, B').
So lets start of with finding out what numbers are a part of group U. By looking at that picture we can see that all number on the graph are a part of group U. So.....
U = {0,1,2,3,4,5,6,7,8,9}
Then we can find out what numbers are part of the group B. We just have to include the numbers that are located within the circle and exclude all of the numbers out side of the circle. So........
B = {0,1,4,5,6,7,8}
We find numbers that are parts of group B' by using a similar method that we used to find out what numbers were part of group B (Just this time we include all numbers outside of the circle and exclude all of the numbers inside the circle). So ......
B' = {2,3,9}
Now we see that the right option is option d.
Answer:
I think he should continue with the same rate of Rs300 per dozen to gain profit of Rs2100
At the rate of Rs 90 pre 5 apples he have to pay Rs 5400 for 300(25 dozen) apples.
total he have 25 dozen of apples.if he sold 12 dozen of appels at 300 per dozen then he earns Rs 3600. according to the merchant goal he wanted to make profit of 2100.we will add rs 2100 to CP hence we will get SP of Rs 5400+2100=7500. if he had already sell 12 dozens at rs 3600 then we will reduce the amount from SP hence we will get Rs 3900 to be earn. 13 dozens of apple is left so we can divide 3900/13 and we will get Rs 300.
if he continues selling those remaining 13 dozens of apple at the same rate the he can make profit of rs 2100.
Answer:
NO.
Step-by-step explanation:
If the 2 prime numbers are odd then the product cannot be a square number because the only factors are the original prime numbers. If one of the prime numbers is 2 then the product will be an even number , but again the only factors will be 2 and the other prime number.
So the answer is No.
