In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
1/8 bowl.
1/2 = 4/8
1/4 = 2/8
1/8 = 1/8
4/8+2/8+1/8 = 7/8
1 - 7/8 = 1/8
I believe the answer is 104.
Area of the triangle = (1/2)*base*height
For right triangle base and height can be legs.
We have one leg = 5 ft. (Lets think it is a base.)
We need to find the other leg.
We are going to use Pythagorean theorem.
5² + b²=13²
b²=144
b=12 (It is going to be our height.)
Area of the triangle = (1/2)*5*12= 30 ft²
Area of the triangle = 30 ft²
