Answer:
There are 685464 ways of selecting the 5-card hand
Step-by-step explanation:
Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.
In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have 
possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.
This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.
THE ANSWER IS .......................... 8.5!!!!
HOPE I HELPED!!!!!!!!
Answer:
(a)
Number of cars with defective turn signals = 65
Number of cars with no defective turn signals = 410 - 65 = 345
<u>Required probability:</u>
- P = 345/410*100% ≈ 84.15%
(b)
Number of cars with defects = 65 + 35 = 100
Number of cars with no defects = 410 - 100 = 310
<u>Required probability:</u>
- P = 310/410*100% ≈ 75.61%
R - 10/3 + 1/2 = -11/6...if u multiply everything by the common denominator 6, it will get rid of the fractions.
(6)r - 6(10/3) + 6(1/2) = 6(-11/6)
6r - 60/3 + 6/2 = - 66/6...simplify
6r - 20 + 3 = - 11
6r - 17 = -11
6r = -11 + 17
6r = 6
r = 6/6
r = 1 <===
