Answer:
2671.3 kJ
Explanation:
m = 866 g at - 10 degree C converts into steam at 126 degree C.
The following steps are there
(1) ice at - 10 degree C converts into ice at 0 degree C
H1 = m x specific heat of ice x ΔT
H1 = 866 x 2.03 x 10 = 17579.8 J
(ii) ice at 0 degree C converts into water at 0 degree C
H2 = m x Latent heat of fusion = 866 x 334 = 289244 J
(iii) water at 0 degree C converts into water at 100 degree C
H3 = m x specific heat of water x ΔT
ΔH3 = 866 x 4.186 x 100 = 362507.6 J
(iv) water at 100 degree C converts into steam at 100 degree C
H4 = m x Lateant heat of vaporisation
H4 = 866 x 2260 = 1957160 J
(v) seam at 100 degree C converts into steam at 126 degree C
H5 = m x specific heat of steam x ΔT
H5 = 866 x 1.99 x 26 = 44806.84 J
The total heat required is
H = H1 + H2 + H3 + H4 + H5
H = 2671298.24 J = 2671.3 kJ
