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3 years ago

6

SOMEONE PLZ HELP. ASAP

1 answer:

Pachacha [2.7K]3 years ago

6 0

Im pretty sure its A

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If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and t

STatiana [176]

Answer:

The velocity is $4.6 m/s^2$

Explanation:

Given:

Force = 500N

Distance s= 0

To find :

Its velocity at s = 0.5 m

Solution:

$\sum F_{x}=m a$

$F\left(\frac{4}{5}\right)-F_{S}=13 a$

$500\left(\frac{4}{5}\right)-\left(k_{s}\right)=13 a$

$400-(500 s)=13 a$

$a = \frac{400 -(500s)}{13}$

$a = (30.77 -38.46s) m/s^2$

Using the relation,

$a=\frac{d v}{d t}=\frac{d v}{d s} \times \frac{d s}{d t}$

$a=v \frac{d v}{d s}$

$v d v=a d s$

Now integrating on both sides

$\int_{0}^{v} v d v=\int_{0}^{0.5} a d s$

$\int_{0}^{v} v d v=\int_{0}^{0.5}(30.77-38.46 s) d s$

$\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}$

$\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]$

$\left[\frac{v^{2}}{2}\right]=[15.385-4.807]$

$\left[\frac{v^{2}}{2}\right]=10.578$

$v^{2}=10.578 \times 2$

$v^{2}=21.15$

$v = \sqrt{21.15}$

$v = 4.6 m/s^2$

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3 years ago

You place a penny on a turntable at a distance of 14.3 cm from the center. The coefficient of static friction between the penny

S_A_V [24]

Answer:

Time will be 2.13 sec

Explanation:

We have given that distance r = 14.3 cm = $=\frac{14.3}{100}=0.143m$

Coefficient of static friction $\mu =0.4$

Angular acceleration is given by $\alpha =2.45rad/sec^2$

We know that frictional force is given by $F=\mu mg$

And centrifugal force is given by $F=\frac{mv^2}{r}$

When coin just starts moving

$\mu mg=\frac{mv^2}{r}$

We know that $v=\omega r$ , here $\omega$ is angular velocity

According to first equation of motion we know that

$\omega =\omega _{i}+\alpha t$

As $\omega _i=0$

so $\omega =\alpha t$

$\mu g=\frac{\left ( r\alpha t \right )^2}{r}$

$\frac{\mu g}{r}=a^2t^2$

$t=\frac{\sqrt{\frac{\mu g}{r}}}{α}$

$t=\frac{\sqrt{\frac{0.4\times 9.8}{0.143}}}{2.45}=2.13sec$

8 0

3 years ago