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Ket [755]
4 years ago
7

The tendency of a stationary object to resist being put into motion is known as _______?

Physics
1 answer:
seropon [69]4 years ago
5 0
Inertia. It also is the tendency of an object in motion to stay in motion in one specific direction.
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The MRI (Magnetic Resonance Imaging) body scanners used in hospitals operate at a frequency of 400 MHz (M = 106 ). Calculate the
horrorfan [7]

Answer:

Energy, E=2.65\times 10^{-25}\ J

Explanation:

It is given that,

The MRI (Magnetic Resonance Imaging) body scanners used in hospitals operate at a frequency of 400 MHz,

\nu=400\ MHz=400\times 10^6\ Hz=4\times 10^8\ Hz

We need to find the energy for a photon having this frequency. The energy of a photon is given by :

E=h\nu

E=6.63\times 10^{-34}\ J-s\times 4\times 10^8\ Hz

E=2.65\times 10^{-25}\ J

So, the energy of the photon is 2.65\times 10^{-25}\ J. Hence, this is the required solution.

6 0
3 years ago
suppose larry stands with more weight on one scale than the other if one scale reads 400 N. what does the other read?
Evgen [1.6K]
The other scale will either have a higher or lower number because 400 could be the bigger number or the smaller number but we don't know that so you cant exactly answer it.<span />
8 0
3 years ago
Read 2 more answers
1. What is the pull that all objects exert on each other?
Andrei [34K]

Answer:

Im pretty sure 1 is gravity, 2 is force

Explanation:

8 0
3 years ago
A block is attached to a spring and rests on a horizontal, frictionless surface. The block is pulled to the right and released f
lana66690 [7]

Answer:

Explanation:

x(t) = (3.5 cm)cos[(0.8 rad/s)t]

Angular velocity ω = .8

Time period = 2π / ω

= 2 X 3.14 / .8

= 7.85 s

First time block will pass through equilibrium is T/4 ,

Second time block will pass through equilibrium

= 3.T/4

= 3/4 x 7.85

= 5.8875 s

6 0
3 years ago
During the hammer throw at a track meet, an 8.0 kg hammer is accidentally thrown straight up. If 784.0 J of
jeka57 [31]

The height risen by the hammer when the work were done is 10 m.

The given parameters;

  • <em>Mass of the hammer, m = 8.0 kg</em>
  • <em>Work done on the hammer, W = 780 J</em>

<em />

Apply work energy - theorem to determine the height risen by the hammer when the work is done on it;

E = mgh\\\\h = \frac{E}{mg} \\\\h = \frac{784}{8 \times 9.8} \\\\h = 10 \ m

Thus, the height risen by the hammer when the work were done is 10 m.

Learn more about work-energy theorem here: brainly.com/question/22236101

4 0
3 years ago
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