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pav-90 [236]
3 years ago
9

The equation of a given circle in general form is x^2+y^2-8x+12y+27=0. Write the equation in standard form, (x-h)^2+(y-k)^2=r^2,

by completing the squares in the equation. Show your work in the table.

Mathematics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

(x - 4)² + (y + 6)² = 5²

Step-by-step explanation:

rearrange the general equation as follows

collect the terms in x and y together and place the constant on the right side

x² - 8x + y² + 12y = - 27

add (half the coefficient of the x/y term)² to both sides

x² + 2(- 4)x + y² + 2(6)y = - 27

(x - 4)² + 16 + (y + 6)² + 36 = - 27 + 16 + 36

(x - 4)² + (y + 6)² = 25

(x - 4)² + (y + 6)² = 5² ← in standard form



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31.5

Step-by-step explanation:

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3 years ago
Choose the property used to rewrite the expression.
Alex73 [517]

The property used to rewrite the given expression is product property.

Answer: Option A

<u>Step-by-step explanation:</u>

Given equation:

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4 0
3 years ago
A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte
monitta

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if it is 0.7 or less, that is:

H_0: \mu \leq 0.7

At the alternate hypothesis, we test if it is greater than 0.7, that is:

H_1: \mu > 0.7

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7

Survey of 35 people. From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that n = 35, X = 0.95, s = 0.44

Calculate the test statistic

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}

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The test statistic is t = 3.36.

7 0
3 years ago
Please help me. What are the correct numbers in this photo?
Marta_Voda [28]

Answer:

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6 0
3 years ago
Some help figuring out the answer?? Also explain a little how you got there
ipn [44]

9514 1404 393

Answer:

  x = 10·cos(θ) -4·cot(θ)

Step-by-step explanation:

Apparently, we are to assume that the horizontal lines are parallel to each other.

The relevant trig relations are ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

If the junction point in the middle of AB is labeled X, then we have ...

  sin(θ) = 4/BX   ⇒   BX = 4/sin(θ)

  cos(θ) = x/XA   ⇒   XA = x/cos(θ)

Then ...

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Substituting for BX and XA using the above relations, we get

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Solving for x gives ...

  x = (10 -4/sin(θ))·cos(θ)

  x = 10·cos(θ) -4·cot(θ) . . . . . simplify

_____

We used the identity ...

   cot(θ) = cos(θ)/sin(θ)

6 0
3 years ago
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