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jolli1 [7]
3 years ago
9

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics
1 answer:
Virty [35]3 years ago
4 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(1-3)^2+(9-6)^2}\implies d=\sqrt{(-2)^2+3^2} \\\\\\ d=\sqrt{13}\implies d\approx 3.6056\implies \stackrel{\textit{rounded up}}{d=3.6}

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Answer:

\boxed{5000}

Step-by-step explanation:

The formula for the amount accrued on an investment earning compound interest is

f(x) = P(1 + r)^{x}

where

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r = the interest rate per payment period expressed as a decimal fraction

t = the number of periods

Your formula is

f(x) = 5000(1 + 0.04)^{x}\\\text{By comparing the formulas, we see that the amount of money invested is $\boxed{\textbf{5000}}$}

4 0
3 years ago
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Write the slope-intercept form of the equation of a line parallel to y=-2/3x+12 that has a y-intercept of -13 (step by step)
USPshnik [31]

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7 0
3 years ago
If a shop earns a profit of 1300 on every heater sold and incurs a loss of 1800 on every fan sold, find out its total profit/ lo
erastovalidia [21]

Answer:

Total profit is 26,900.

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5 0
3 years ago
a model of a car is amde to a scale of 1:40. the volume of the model is 45cm^3. calcualte the volume of the car. give your answe
spin [16.1K]

The volume of the car is 1800cm^3 which is equivalent to 0.0018m^3

<h3>Scale modelling</h3>

Given the scale factor that model of a car is amde to a scale of 1:40, Giving that the model as 45cm^3, this means that;

1 = 45cm^2

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40 = x

Find the ratio

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x = 1800cm^3

x = 0.0018m^3

Hence the volume of the car is 1800cm^3 which is equivalent to 0.0018m^3

Learn more on scale factor here; brainly.com/question/25722260

#SPJ1

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2 years ago
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