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3 years ago

If the volume of the gas increased from 600 to 800 in.^3, by how much does the pressure change?

Mathematics

2 answers:

AlekseyPX3 years ago

8 0

Answer:

The answer is " it decreases by 7.5 psi "

Step-by-step explanation:

just failed to answer it lol

lukranit [14]3 years ago

4 0

Answer:

It decreases by 7.5 psi

Step-by-step explanation:

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Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16

HACTEHA [7]

Answer: The scale factor of the dilation is 0.5.

Explanation:

It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.

The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.

The reflection affects the coordinates but does not affect the length of the sides.

But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.

If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.

$|A'B'|=k\times |AB|$ .... (1)

So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.

Use distance formula to find the side length.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}$

$PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}$

It is noticed that the size of side in preimage is $2\sqrt{13}$ and the size of same side in image is $\sqrt{13}$ .

Using equation (1), we get

$\sqrt{13}=k \times 2\sqrt{13}$

$k=\frac{1}{2}$

$k=0.5$

Hence, the value of scale factor is 0.5.

7 0

3 years ago

Read 2 more answers

a person bought two watches for 2500, she sold one of them at 10% profit & the other one at 4% loss. what was her gain or lo

Zepler [3.9K]

Answer:

profit : RS 150 and profit % : 3%

Step-by-step explanation:

for profit 10% for loss 4%

s.p will be 2750. s.p will be 2400

Total s.p : 2750 +2400. total s.p : 5150

profit = s.p-c.p. profit%=?

=5150-5000. profit = p /c.p × 100

=150 = 150/5000×100

= 3%

8 0

2 years ago

Plz help!!!! Number 23

Minchanka [31]

Answer:

(0 + m)/2, (0 + n)/2.

Step-by-step explanation:

The x coordinate of the midpoint must be halfway between the x coordinates of A and B, and the y coordinate must be found in the same way.

So the midpoint is (0 + m)/2, (0 + n)/2.

7 0

3 years ago

If the student is a domain/inout and the hair color is the range/output how is these two set of relation not a function?

IRINA_888 [86]

Answer:

A function is a relation that maps inputs from a set called the domain, into outputs from a set called the range.

Such that each input can be mapped into only one output.

So for example, if we have a relation that maps the input 2 into two different values:

f(2) = 4

f(2) = 8

Then this is not a function.

In the case of the problem, we have a student as the input, and the hair color as the output.

So we will have something like:

f(student) = blond

And if this student decides to change his/her hair color to red?

Then the function becomes:

f(student) = red

So for the same input, we had two different outputs, which means that this is not a function.

We also could have the case where a given student has two colors (Californian for example)

Where again, we would see two different outputs for one single input.

6 0

2 years ago

At work, Elon takes a break 1/5 of each hour he works. He also takes a lunch break for 1/2 of an hour each day he works. Elo

Anton [14]

Answer:

$h=50\ hours$

Step-by-step explanation:

Let

h -----> the number of hours, Elon works during one 5-day work week

we know that

$12\frac{1}{2}\ h=\frac{12*2+1}{2}=\frac{25}{2}\ h$

Elon’s break time must be equal to 1/2 of an hour multiplied by 5 days plus 1/5 multiplied by the total hours h

$\frac{25}{2}=5(\frac{1}{2})+\frac{1}{5}h$

Solve for h

Multiply by 10 both sides to remove the fraction

$125=25+2h$

$2h=125-25$

$2h=100$

$h=50\ hours$

8 0

3 years ago

If the volume of the gas increased from 600 to 800 in.^3, by how much does the pressure change?​

If the volume of the gas increased from 600 to 800 in.^3, by how much does the pressure change?