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vampirchik [111]
3 years ago
10

Find the vertex of " "y = x^2 + 5x+ 4" please show steps as well thanks

Mathematics
2 answers:
zlopas [31]3 years ago
8 0
(x^2 +5x+2.5^2) +4+5

(x+2.5)^2+9

vertex -2.5,9
Juli2301 [7.4K]3 years ago
3 0
Vertex of the equation is (-2.5, -2.25) 

y=x^2+5x+4 ----> find x using -b/2a

-5/2=-2.5

Now plug it in the equation to find the y-value

(-2.5)^2+5(-2.5)+4=-2.25
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Let's work on the left side first. And remember that
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Substitute for the tangent:

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Cancel the cos(a) from the top and bottom, and you're left with

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Multiply that all out, using FOIL:

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Whew !





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