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3 years ago

Find the vertex of " "y = x^2 + 5x+ 4" please show steps as well thanks

Mathematics

2 answers:

zlopas [31]3 years ago

8 0

(x^2 +5x+2.5^2) +4+5

(x+2.5)^2+9

vertex -2.5,9

Juli2301 [7.4K]3 years ago

3 0

Vertex of the equation is (-2.5, -2.25)

y=x^2+5x+4 ----> find x using -b/2a

-5/2=-2.5

Now plug it in the equation to find the y-value

(-2.5)^2+5(-2.5)+4=-2.25

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<h3>Further explanation</h3>

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<em>Let us tackle the problem!</em>

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This problem is about Directly Proportional.

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<h3>Learn more</h3>

Infinite Number of Solutions : brainly.com/question/5450548
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<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

7 0

4 years ago

Find the quotient. -300x5y4 ÷ xy2 -150 x6y6 -300 x6y6 300 x4y2 -300 x4y2

exis [7]

Answer:

d. -300 x4y2

Step-by-step explanation:

Here is the correct question: Find the quotient. -300x5y4 ÷ xy2

a. -150 x6y6

b. -300 x6y6

c. 300 x4y2

d. -300 x4y2.

Given: -300x5y4 ÷ xy2

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Using law of indices to solve it.

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3 years ago

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4 years ago