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andrezito [222]
2 years ago
7

For exercises 1-4. use the drawing and an inch ruler to find the actual length and width of each section of the park. Measure to

the nearest eighth of an inch. What is the scale factor of the park plan?
Mathematics
1 answer:
julsineya [31]2 years ago
4 0

Answer:

Step-by-step explanation:

Isaiah Let's solve this by rewriting the actual measurements the two boys have with their uncertainties. Krisann has a measuring tape to the nearest quarter inch. So his measurement may be off by half that, or and eighth of an inch. So his measurement is 27.75 ± 0.125. Isaiah has a measuring tape to the nearest eighth inch. So his measurement may be off by up to a sixteenth of an inch. So his measurement is 27.75 ± 0.0625 Now which is more precise, 27.75 ± 0.125, or 27.75 ± 0.0625? The answer is pretty obvious with 27.75 ± 0.0625 being the more precise measurement. And that value is from Isaiah.

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345+ 223<br> Use rounding or compatible numbers to estimate the sum
Mars2501 [29]
I think it is 568 if I’m not mistaken
8 0
3 years ago
NEED ASAP!!
iris [78.8K]

Hey!

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Answers:

B-B-A-B

A-B-B-B

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6 0
3 years ago
Read 2 more answers
Y = -3x + 11<br> y = -6x - 13
Marysya12 [62]

Answer:

x= -8 and so y=35.....solving equation

5 0
3 years ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}

\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

5 0
2 years ago
Someone please help me
allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

4 0
2 years ago
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