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STatiana [176]
4 years ago
7

A pitcher has 16 cups of water in it. During the day, Aditi drank 21⁄2 cups, Kavitha drank 33⁄4 cups, and Rahul drank 41⁄8 cups.

How many cups of water are still in the pitcher?
Mathematics
1 answer:
zepelin [54]4 years ago
8 0

Total cups of water in pitcher = 16 cups

Cups of water drank by Aditi = 2 \frac{1}{2} = \frac{5}{2} cups

Cups of water drank by Kavitha = 3 \frac{3}{4}=  \frac{15}{4} cups

Cups of water drank by Rahul = 4 \frac{1}{8}=  \frac{33}{8} cups

Total cups of water drank by three of them

= \frac{5}{2} +  \frac{15}{4} + \frac{33}{8}

LCM of 2,4 and 8 is 8.

= \frac{20+30+33}{8}

= \frac{83}{8} cups

Number of cups left in the pitcher = 16 - \frac{83}{8}

LCM of 1 and 8 is 8.

= \frac{128-83}{8}

= \frac{45}{8}

=5 \frac{5}{8} cups

So, 5 \frac{5}{8} cups are left in the pitcher.

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