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2 years ago

Dan found a two digit odd number one of its digits was half the other the number was greater than 50 what number did Dan find?

1 answer:

4 0

If the last number is 1 -> 21 <50
if the last number is 3 -> 63 > 50 OK
if the last number is 5 -> 105 which is not a two digits number

if the first number is 4 -> 42<50
if the first number is 6 -> we get 63 again
if the first number is 8 -> we get 83 which is not odd

63 is the only answer

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The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

According to the given question.

We have an equation

$\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}$

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

$\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}$

$\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}$

$\implies \frac{x^{2}-x-6 }{x^{2} } = \frac{5x +18}{2x}$

Multiply both the sides by x.

$\frac{x^{2}-x-6 }{x} = \frac{5x+18}{2}$

Again multiply both the sides by x

$2x^{2} -2x-12 = 5x^{2} +18x$

$\implies 5x^{2} -2x^{2} +18x +2x +12 = 0$

$\implies 3x^{2} + 18x+2x + 12 = 0$

Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

Find out more information about equation here:

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1 year ago

Answer please i am literally crying because i will get in trouble if i dont do it

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Then multiply those together:
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P.S. You can convert percentages to units by diving % by 100 for example 100% divided by 100 is equal to 1.
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