All categories

2 years ago

Solve. 6y=192 a. -32 b. -18 c. 18 d. 32

1 answer:

5 0

(the opposite of the multiplication of 6 is to divide each side by 6)

6y = 192

6y ÷ 6 = 192 ÷ 6

y = 192 ÷ 6

y = 32

The answer is D. 32

You might be interested in

Please help with this question

insens350 [35]

Answer:

alternate interoir

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is the median of the following data set -1000, -999, 1998, ..., -1, 0, 1, ..., 998, 999, 1000

qwelly [4]

Answer:

The correct answer option is C. 0.

Step-by-step explanation:

We are given the following data set and we are to find its median value:

$- 1 0 0 0 , - 9 9 9 , 1 9 9 8 , ... , -1 , 0 , 1 , ... , 9 9 8 , 9 9 9 , 1 0 0 0$

Median is the middle value of a data set which divides it into to halves.

The data set we have starts from -1000 and goes till 1000 which means there are total 2001 elements in it.

Therefore, 0 will the middle value which is the median for this data set.

7 0

2 years ago

Read 2 more answers

A rectangle has 3 square feet and width 1/2 foot. What is the length of the rectangle

Yakvenalex [24]

Answer:

We Know, Area = Length * Width

Here, A = 3

W = 1/2

Substitute it into the expression,

3 = L * 1/2

L = 3/ 1/2

L = 3/2 ft²

So, the length of the rectangle would be 3/2 ft²

Hope this helps! :)

8 0

3 years ago

Solve: x + 6 = -11 May I please have help with this?!

klemol [59]

Answer:

x=-17

Step-by-step explanation:

subtract 6 from each side and simplify and you'll get -17

3 0

2 years ago

Read 2 more answers

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

3 years ago