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oee [108]
3 years ago
7

Not sure how to solve this :/

Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

SAME

Step-by-step explanation:

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Two photos were taken of a car.
LenKa [72]

Answer:

14.4 m / s

Step-by-step explanation:

=distance between the car

=0.8 × 9

=7.2m

=time taken

=0.5s

=speed

=distance/time

=7.2m/0.5s

=14.4 m / s

4 0
3 years ago
For the month of march, Kasey plans to vacuum her floor every fourth day and clean her bathroom every seventh day if she begins
Alexeev081 [22]

Answer: March 28

Step-by-step explanation:

Solve for this by checking for the lowest common multiple of 7 and 4.

Multiples of 7: 7, 14, 21, 28, 35

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32

Lowest is 28 so on March 28th she both will vacuum her floor and clean her bathroom.

4 0
3 years ago
Solve for m. 4 = 20m Simplify your answer as much as possible.
iris [78.8K]

Answer:

0.2

Step-by-step explanation:

5 0
3 years ago
Convert 100 inches per minute to feet per hour?
docker41 [41]
100 inches per minute
There are 60 minutes per hour so
100 inches per minute equals
6,000 inches per hour
there are 12 inches per foot so that converts to
500 feet per hour



8 0
3 years ago
A study was conducted to measure the effectiveness of hypnotism in reducing pain. The measurements are centimeters on a pain sca
inna [77]

Answer:

Step-by-step explanation:

Hello!

This is an example of a pared sample test, the experiment is based on two dependent variables:

X₁: centimeters on a pain scale before hypnosis

X₂: centimeters on a pain scale after hypnosis

Out of these two variables a new variable is determined Xd= X₁-X₂

If the variables have an approximate normal distribution then the variable resulting from their difference will also have an approximate normal distribution.

The claim is that "hypnosis reduced the pain" if so you'd expect the population mean of the difference to be less than zero, symbolically: μd<0

The statistic for this test is a paired sample t test:

t= \frac{\frac{}{X_d} - Mu_d}{Sd} ~t_{n-1}

To calculate the sample mean and variance you have to calculate the difference between the pairs first.

\frac{}{Xd}= ∑Dif/n

S_d^2= \frac{1}{n-1} [sumDif^2- \frac{(sumDif)^2}{n} ]

∑Dif= 6.4

∑Dif²= 12.64

\frac{}{Xd}= 6.4/5= 1.28

S_d^2= \frac{1}{4} [12.64- \frac{(6.4)^2}{5} ]= 1.112

Sd= 1.05

t_{H_0}= \frac{\frac{}{Xd}-Mu_d }{Sd} = \frac{1.28-0}{1.05} = 1.219= 1.22

I hope this helps!

7 0
4 years ago
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