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lbvjy [14]
2 years ago
10

9n - 4 + n = 5 + 10n

Mathematics
2 answers:
sergejj [24]2 years ago
8 0
The answer would be 0=9
just olya [345]2 years ago
7 0

Answer:

0=9 or NO SOLUTION

Step-by-step explanation:

9n−4+n=5+10n

9n+−4+n=5+10n

(9n+n)+(−4)=10n+5(Combine Like Terms)

10n+−4=10n+5

10n−4=10n+5

Step 2: Subtract 10n from both sides.

10n−4−10n=10n+5−10n

−4=5

Step 3: Add 4 to both sides.

−4+4=5+4

0=9

(please mark this brainliest)

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Write the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5).
lys-0071 [83]

Answer:

(x+1)^2 + (y- 3.5)^2 =64

Step-by-step explanation:

We are given that  endpoints of a diameter at the points (7,2) and (-9,5).

Center of the circle is the mid point of diameter

So, first find the mid point of diameter

Formula : x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

Substitute the values in formula

x=\frac{7-9}{2} , y=\frac{2+5}{2}

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So, center of circle = (h,k )=(-1,3.5)

To find length of diameter :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

d=\sqrt{(-9-7)^2+(5-2)^2}

d=\sqrt{265}

Length of radius = r = \frac{Diameter}{2}=\frac{\sqrt{256}}{2}

Standard form of the equation of the circle : (x -h)^2 + (y- k)^2 = r^2

(h,k )=(-1,3.5)

r=\frac{\sqrt{256}}{2}

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =64

Hence  the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is  (x+1)^2 + (y- 3.5)^2 =64

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Step-by-step explanation:

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