To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
To find the length of the ladder, you need to do Pythagorean theorem.
50^2 + 30^2 = x^2
2500 + 900 = x^2
x^2 =3400
x= square root of 3400
58.31 OR 10 root34
To find the angle:
tan theta = opposite/adjacent
50/30 = 5/3
theta = tan inverse of 5/3
= 59.04
AND?!?
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Answer:
Debit Cost of Goods Sold $710
Credit Material Price Variance $40
Credit Material Usage Variance $225
Credit Labor Rate Variance $110
Credit Labor Efficiency Variance $335
Step-by-step explanation:
Preparation of the journal entry to be passed by Theta Company at the end of the month of February to close the variances
Debit Cost of Goods Sold $710
($40+$225+$110+$335)
Credit Material Price Variance $40
Credit Material Usage Variance $225
Credit Labor Rate Variance $110
Credit Labor Efficiency Variance $335
(To close the variances)
