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Mama L [17]
3 years ago
6

PLease school is almost over HELP 30x+60x=?

Mathematics
2 answers:
kolezko [41]3 years ago
8 0

Answer:

90x

Step-by-step explanation:

30x+60x=?

If you want to solve this easily, you can just remove x and add 30x + 60x.

30+60

We know that 30 + 60 is 90. So we will add x to 90.

90x

Now you have your answer!

Hope this helps!

dimaraw [331]3 years ago
6 0

Answer:

90x

Step-by-step explanation:

To solve, add 30+60.

30 + 60 is equal to 90.

Add x and it will be 90x.

That is your answer!

Hope I helped!

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3 years ago
Can someone help me my class is at 9
ololo11 [35]

Answer: 1/4

Step-by-step explanation: 20 is a fourth of 80

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6 0
3 years ago
How can i solve by completing the square 4r^2-28r=-49
Natalija [7]
To complete the square, the second degree term must have a coefficient of 1.
Since the second degree term here has a coefficient of 4, we start by dividing each term on both sides by 4.

4r^2 - 28r = -49

\dfrac{4r^2}{4} - \dfrac{28}{4}r = -\dfrac{49}{4}

r^2 - 7r = -\dfrac{49}{4}

Now we can complete the square.
First, we need to find what number completes the square.
We take the coefficient of the first degree term, -7 in this case.
Divide it by 2 and square it. -7 divided by 2 is the fraction -7/2.
Now we square -7/2 to get 49/4.
We add 49/4 to both sides.

r^2 - 7r + \dfrac{49}{4} = -\dfrac{49}{4} + \dfrac{49}{4}

(r - \dfrac{7}{2})^2 = 0

r - \dfrac{7}{2} = 0

r = \dfrac{7}{2}
3 0
4 years ago
Kai wrote the number 85 on the board is 85 prime or composite?
laila [671]
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4 0
3 years ago
Read 2 more answers
A fire hydrant with a blue cap provides water at a rate of 1,500 gallons per minute. A fire hydrant with a green cap provides wa
lapo4ka [179]

Answer:

a) 2b = 3g

b) 3p = b

Step-by-step explanation:

Given:

Fire hydrant with a blue cap, b, provides water at a rate = 1500 gallons per min

Fire hydrant with a green cap, g, provides water at a rate = 1000 gallons per min

Fire hydrant with a purple cap, p, provides water at a rate = ½g = \frac{1}{2}*1000 = 500

a) The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g.

Given flow of blue hydrant, b = 500

Simplifying, we have:

b = 3*500

b = 3 * \frac{1000}{2}

Since the flow rate of green hydrant, g, is 1000, let's replace 1000 with g above.

Therefore,

b = 3 * \frac{g}{2}

b = \frac{3}{2}g

Cross multuply

2b = 3g

The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g is 2b=3g.

b) An equation to relate the flow of water from the purple hydrant, p, to the flow from the blue hydrant, b.

Given flow rate of purple hydrant, p = 500

It could also be re-written as:

\frac{3}{3} * 500

p = \frac{1500}{3}

Since the flow rate of blue hydrant, b, is 1500, let's replace 1500 with b above.

p = \frac{b}{3}

Cross multiply

3p = b

8 0
3 years ago
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