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2 years ago

PLease school is almost over HELP 30x+60x=?

Mathematics

2 answers:

kolezko [41]2 years ago

8 0

Answer:

$90x$

Step-by-step explanation:

$30x+60x=?$

If you want to solve this easily, you can just remove x and add 30x + 60x.

$30+60$

We know that 30 + 60 is 90. So we will add x to 90.

$90x$

Now you have your answer!

Hope this helps!

dimaraw [331]2 years ago

6 0

Answer:

90x

Step-by-step explanation:

To solve, add 30+60.

30 + 60 is equal to 90.

Add x and it will be 90x.

That is your answer!

Hope I helped!

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Which absolute value expression represents the distance between 3 and −5 on a number line?

lora16 [44]

Answer:

B) To represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .

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Here the point A is given as 3 on number line.

Point B is given as -5 on number line.

To find : IA-BI

The distance between any two point A and B is given as IA-BI.

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IA-BI = I (3) - (-5)I

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= 8 units

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2 years ago

At the zoo tje ratio of snakes to lizards is 3:2 A. If there were 10 lizards ,how many snakes would be there be? B.If there were

yawa3891 [41]

Answer:

Part A) $15\ snakes$

Part B) $6\ lizards$

Part C) The zoo would need to get four more lizards to maintain the same proportion

Part D) 12 snakes and 8 lizards

Step-by-step explanation:

Part A) If there were 10 lizards ,how many snakes would be there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

we have that

$y=10\ lizards$

substitute the value of y in the equation A

$\frac{x}{10}=\frac{3}{2}$

solve for x

$x=10(3)/2\\x=15\ snakes$

Part B) If there were 9 snakes ,how many lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

we have that

$x=9\ snakes$

substitute the value of x in the equation A

$\frac{9}{y}=\frac{3}{2}$

solve for y

$y=9(2)/3\\y=6\ lizards$

Part C) If the number of snakes in the zoo is increased by 6, how many more lizards would the zoo need to get to keep the same ratio?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

For $x=6\ snakes$

substitute the value of x in the equation A

$\frac{6}{y}=\frac{3}{2}$

solve for y

$y=6(2)/3\\y=4\ lizards$

therefore

The zoo would need to get four more lizards to maintain the same proportion

Part D) If the total number of snakes and lizards at the zoo was 20, how many snakes and lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$

isolate the variable x

$x=1.5y$ ----> equation A

$x+y=20$ ----> equation B

solve the system by substitution

substitute equation A in equation B

$1.5y+y=20$

solve for y

$2.5y=20$

$y=8\ lizards$

Find the value of x

$x=1.5(8)=12\ snakes$

therefore

12 snakes and 8 lizards

8 0

2 years ago