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kobusy [5.1K]
3 years ago
9

Can someone help with this graph problem? I really need help on it, I'd appreciate it alot :)

Mathematics
1 answer:
Ainat [17]3 years ago
7 0
Im pretty sure is teh 3rd one
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Name the angle pair: ∠5 and ∠8
Mekhanik [1.2K]

Answer:

The correct answer would be vertical angles

Step-by-step explanation:

The answer is vertical angles because the two lines make an acute angles that are equal to each other on both sides. I hope this helped!!! Have a good day!!!

5 0
3 years ago
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Multiply. Answer with a mixed number in simplest form.<br><br> 5 x 2 1/4
soldier1979 [14.2K]

Answer:

The correct answer should be 11\frac{1\\}{4}

Step-by-step explanation:

Let me know if this is wrong and I will correct it if it is.

3 0
3 years ago
I need help with this logic puzzle,
natka813 [3]
I cannot reach a meaningful solution from the given information. To prove that S was always true, you would have to prove that N was always false. To prove that N was always false you would have to prove that L was always false. For the statement (L ^ T) -> K to be true, you only need K to be true, so L can be either true or false.
Therefore, because of the aforementioned knowledge, I do not believe that you can prove S to be true. 
3 0
3 years ago
Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

4 0
3 years ago
What is the value of x?
uranmaximum [27]

Answer:

x=\frac{160-51}{2} =54.5°

Step-by-step explanation:

"Theorem 9-13: The measure of an angle formed by two secants, two tangents, or a secant and a tangent drawn from a point outside the circle is equal to half the difference of the measures of the intercepted arcs."

Basically no matter what other circle, secant or tangent you get, you just use the formula Outer\angle=\frac{far.point - near.point}{2}

If you need the outer angle, just put the other angles in and solve

If you need the far or near point angle, re-arrange the formula to get that value.

6 0
3 years ago
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