Consider the radical equation VC+22 = c + 2. Which statement is true about the solutions c = 3 and c =-6?

Pattern A was created by using the rule "start at 2 and add 3." Pattern B was created by using the rule "start at 14 and subtrac

uysha [10]

Answer:

(2, 14), (5, 12), (8, 10), (11, 8), (14, 6)

Step-by-step explanation:

Lets do the math for Pattern A:

2 + 3 = 5

5 + 3 = 8

8 + 3 = 11

11 + 3 = 14

Lets do the math for Pattern B:

14 - 2 = 12

12 - 2 = 10

10 - 2 = 8

8 - 2 = 6

6 - 2 = 4

7 0

3 years ago

A group of friends were working on a student film that had a budget of $700. They used 42% of their budget on equipment. How muc

goldfiish [28.3K]

Answer:

294

Step-by-step explanation:

100%-> 700

42%->294

5 0

3 years ago

The Office of Student Services at a large western state university maintains information on the study habits of its full-time st

Vera_Pavlovna [14]

Answer:

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20 hours, standard deviation of 6:

This means that $\mu = 20, \sigma = 6$

Sample of 150:

This means that $n = 150, s = \frac{6}{\sqrt{150}}$

What is the probability that the mean of this sample is between 19.25 hours and 21.0 hours?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.5. So

X = 21

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{21 - 20}{\frac{6}{\sqrt{150}}}$

$Z = 2.04$

$Z = 2.04$ has a p-value of 0.9793

X = 19.5

$Z = \frac{X - \mu}{s}$

$Z = \frac{19.5 - 20}{\frac{6}{\sqrt{150}}}$

$Z = -1.02$

$Z = -1.02$ has a p-value of 0.1539

0.9793 - 0.1539 = 0.8254

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

3 0

3 years ago

Find the circumference of the circle below to the nearest tenth Use 3.14 for a

AnnyKZ [126]

Answer:

125.6

Step-by-step explanation:

all you have to do is multiple the 3.14 with 40 cm to get 125.6 cm

8 0

3 years ago

Write an expression for the calculation the difference of the products of 5 and 2 and 5 and 1

oee [108]

Let's review the terminology. A product is what you get when you multiply two numbers. So, the product of 5 and 2 is basically "5*2," and the product of 5 and 1 is "5*1."

The difference means when you subtract one from the other. So, the difference of 5*2 and 5*1 means "(5*2)-(5*1)". (Note: I put in parentheses to make sure the reader understands that 5*2 is separate from 5*1. 5*2-5*1 is confusing: you might not know what to do first!)

So, "(5*2)-(5*1)" can be your answer, OR you can simplify it further by actually doing the multiplication: "10-5". If you want the answer, just subtract--the expression is equal to 5.

Answer: "<span>(5*2)-(5*1)" OR "10-5" OR "5"</span>

3 0

4 years ago