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tigry1 [53]
2 years ago
11

In a week, a given stock gained 6 points, dropped 13 points, dropped 3 points, gained 15 points, and dropped 10 points. What was

the net change in the stock's worth?
Mathematics
1 answer:
Brrunno [24]2 years ago
6 0

6 - 13 - 3 + 15 - 10 = -5

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How much is 75% of 10 liter of milk?
enyata [817]

Answer:

7.5 liters of milk

Step-by-step explanation:

Multiply 10 by 0.75

Hope that helps!

4 0
2 years ago
2. Find the area of a circle with a diameter of 10<br> feet.
Paha777 [63]

Step-by-step explanation:

d=2r

πr^2

10/2=r

5=r

5^2π

25π=78.5398

Hope that helps :)

8 0
2 years ago
Read 2 more answers
Roger has 2 1/2 cups of butter. A recipe for a loaf of bread requires 3/4 cup of butter. How many loaves can roger bake?
Alchen [17]

In order to calculate the number of loaves Roger can bake, we should calcculate how many times 3/4 (required butter for one loaf of bread) is included in 2 1/2 (amount of butter Roger has).

2 1/2=4/2+1/2=5/2

(5/2)/(3/4)=5*4/2*3=20/6=3,33

Roger can bake 3 loaves of bread.

3 0
3 years ago
a line segment with points p(1 2) and q(4 3) is reflected across the line y=x. What are the new coordinates of the points of the
katen-ka-za [31]

Answer:

The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)

Step-by-step explanation:

we know that

When you reflect a point across the line y= x, the x-coordinate and y-coordinate change places.

so

The rule of the reflection of a point across the line y=x is

(x,y) -----> (y,x)

we have

Points p(1,2) and q(4,3)

Applying the rule of the reflection across the line y=x

p(1,2) ------> p'(2,1)

q(4,3) -----> q'(3,4)

therefore

The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)

3 0
3 years ago
A square and an equilateral triangle have equal perimeters. the area of the triangle is 
Ivenika [448]

a - length of side of a square

t - length of side of a triangle

The perimeter of a square: P_S=4a

The perimeter of a triangle: P_T=3t

We have the area of a triangle: A_T=16\sqrt3\ cm^2

The formula of an area of an equilateral trinagle: A_T=\dfrac{t^2\sqrt3}{4}

Substitute:

\dfrac{t^2\sqrt3}{4}=16\sqrt3    <em>multiply both sides by 4</em>

t^2\sqrt3=64\sqrt3     <em>divide both sides by \sqrt3</em>

t^2=64\to t=\sqrt{64}\to t=8\ cm

The perimeter of a triangle: P_T=3(8)=24\ cm

Substitute to the formula of a perimeter of a square:

4a=24       <em>divide both sides by 4</em>

a=6\ cm

The formula of a diagonal of a square: d=a\sqrt2

Substitute:

d=6\sqrt2\ cm

3 0
2 years ago
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