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3 years ago

5

two airplane fly toward each other from points 900 miles apart, at the rate, per hour, of 300 miles and 250 miles. when will the

y meet if they start at the same instant?

1 answer:

Lapatulllka [165]3 years ago

8 0

They get 550 miles closer per hour. 900/550=1.636363.... They will meet after 1.64 hrs

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FinnZ [79.3K]

1 $\frac{11}{16}$ is the answer you're looking for.

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3 years ago

2. What is the place value of the "6" in the number: 181,452.836? *

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3 years ago

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3 years ago

Which equation is solved for the variable h? v=by/3

max2010maxim [7]

The equation is given as: v=by/3 but it is actually <span>v=bh/3
</span><span>
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4 years ago

A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects

Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let <em>X</em> denote the number of green candies.

The probability of green candies is, <em>p</em> = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, <em>n</em> = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable <em>X</em> follows a binomial distribution with parameter <em>n</em> = 30 and <em>p</em> = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

$P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328$

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

= 0.17228 + 0.17946 + 0.15328

= 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

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3 years ago