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Arisa [49]
3 years ago
11

Match each equation to its solution.

Mathematics
2 answers:
nlexa [21]3 years ago
7 0

Answer:

i)x=6

ii) x=-7

iii) x=-5

Step-by-step explanation:

First take the no. to the other sides. Then divide, then u will get x

astra-53 [7]3 years ago
4 0
Good job you got it right! But others won’t be able to find it because you have a basic writing for it. Next time put the actual equations on so others can find it!
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Line f has a slope of -3. what is the slope of the line that is parallel to line f
andre [41]

Answer:

A line parallel has the same slope, so -3

8 0
2 years ago
This equation shows how the time required to ring up a customer is related to the number of items being purchased. t = 4p + 20 T
konstantin123 [22]

Answer:

6 items are being purchased

Step-by-step explanation:

Given that  variable p represents the number of items being purchased, and the variable t represents the time required to ring up the customer, If it takes 44 seconds to ring up a customer then the number of items being purchased may be computed by substituting the value of t into the given equation

t = 4p + 20.

Using t = 44

44 = 4p + 20

collect like terms or subtract 20 from both sides

44 - 20 = 4p

24 = 4p

Divide both sides by 4

24/4 = p

p = 6

4 0
3 years ago
PLeAsE sEnD hElP !!!!!!!!!!!!!!!!
Luba_88 [7]

Answer:

5 units

Step-by-step explanation:

If DG, EG and FG are perpendicular bisectors of the sides of triangle ABC, then point G is the circumcenter of the triangle ABC and

BG = AG = CG as radii of the circumcirle.

Consider right triangle BEG. By the Pythagorean theorem,

BG^2=EG^2+BE^2\\ \\BG^2=4^2+3^2\\ \\BG^2 =16+9\\ \\BG^2=25\\ \\BG=5\ units

This gives us that

AG = BG = 5 units

3 0
2 years ago
The speeds (in miles per hour) of motorists ticketed during one day on a five-mile stretch of highway are
Inga [223]

Answer:

19

Step-by-step explanation:

Range is solved by subtracting the lowest and highest numbers which int his case is 70 and 89 so that make 19

8 0
2 years ago
Mr suresh had 7/9 kg of sugar. He used 1/3 of it. How much sugar did he use?​
BabaBlast [244]

1/3 * 7/9 kg = (1 * 7)/(3 * 9) kg = 7/27 kg

He used 7/27 kg of sugar.

3 0
2 years ago
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